Which combination of parameters will produce the same radiographic exposure as 200 mA, 1/5 second, 60 kVp?

To determine which combination of parameters produces the same radiographic exposure as 200 mA, 1/5 second, and 60 kVp, we need to focus on factors that influence exposure: the product of milliamperes (mA) and time (seconds) gives the total milliampere-seconds (mAs), which directly correlates with exposure.

The original setting of 200 mA for 1/5 second can be calculated as follows:

[ 200 , \text{mA} \times 0.2 , \text{s} = 40 , \text{mAs} ]

This means that in order to achieve the same exposure of 40 mAs, the other combinations must yield the same.

Now, let's analyze the other options:

In the first alternative of 200 mA and 1/10 second:

[ 200 , \text{mA} \times 0.1 , \text{s} = 20 , \text{mAs} ]

This is less than the required 40 mAs.

In the second alternative of 400 mA and 1/10 second:

[ 400 , \